7-5

tanX=3/4  pie<X<2pie

r^2=3^2+4^2                      cosX= -4/5
r^2=9+16                            sinX= 3/5
r^2=25                                cotX= 4/3
r=5                                      cscX= 5/3
                                            secX= -5/4

To start to solve this problem, you have to identify what quadrant it is in.  We are given pie<X<2pie for this problem.  Since pie is 180 and 2pie is 90, the quadrant that is in the middle of those two is quadrant two.  Then we see that we are given tanX=3/4, so we have to find all 5 other trig functions.  To start off it's easier if you draw the triangle thing Brob taught us.  We have to find the radius first.  So you use pathagorian theorem which is a^2+b^2=c^2.  We get 5 as our radius.  Then we have to identify was functions are negative and positive.  In quadrant two, sin is positive, cos is negative, and tan is negative.  Now you just find the five other trig functions with all the data you just figured out.  CosX is x/r, SinX is y/r, CotX is x/y, CscX is r/y, SecX is r/x, and TanX is y/x.   So cosX would be -4/5, sinX would be 3/5, cotX would be 4/3, cscX would be 5/3, and secX would be -5/4.