~tan(A+B)= (tanA + tanB)/(1-tanAtanB)
~tan(A-B)= (tanA- tanB)/(1+tanAtanB)
YOU MUST USE THE FORMULAS!
______________________________________________________________________________
Ex.1: Suppose tanA=2 and tanB=6; Find tan(A+B):
tan(A+B)=(2+6)/(1-2*6)
=8/1-12
tan(A+B)=-8/11
Ex.2: Suppose tanA=1/2 and tanB=3/4; Find tan(A-B):
tan(A-B)=(1/2-3/4)/(1+1/2*3/4)
=(-1/4)/(1+3/8)
-1/4/11/8= -8/44
tan(A-B)=-2/11
Ex.3: Suppose tanA=3 and tanB=5; Find tan(A-B):
tan(A-B)=(3-5)/(1+3*5)
=-2/1+15
=-2/16
tan(A-B)=-1/8
Ex.4: Suppose tanA=1/6 and tanB=2/3; Find tan(A+B):
tan(A+B)=(1/6+2/3)/(1-1/6*2/3)
=5/6/8/9
=45/48
tan(A+B)=15/16
No comments:
Post a Comment