Law of Sines!

*I just got back from retreat and I am beyond tired, so im gonna try to hurry and finish this so I get some sleep before your test tomorrow..

--You can only use Law of Sines in a non-right triangle when you have a "pair", which is an angle and opposite side.

Formula:
sinA/a=sinB/b=sinC/c

--You cross multiply to solve.

--Two answers for inverse (you must check to see if they work).

Example 1:
Solve triangle ABC.
angleA=45degrees
angleB=60degrees
side a=14

sin45/14=sin60/b
bsin45=14sin60
divide both sides by sin45 to get b by itself
b=17.146
180-60-45=75degrees
angleC=75degrees
sin45/14=sin75/c
csin45=14sin75
divide both sides by sin45 to get c by itself
c=19.124degrees

Example 2:
Solve triangle ABC.
angleB=30degrees
angleA=135degrees
side b=4

sin30/4=sin135/a
asin30=4sin135
divide both sides by sin30 to get a by itself
a=5.657degrees
180-30-135=15
angleC=15degrees
sin30/4=sin15/c
csin30=4sin15
divide both sides by sin30 to get c by itself
c=2.07degrees

Example 3:
Solve triangle ABC.
angleC=25degrees
side b=3
side c=2

sin25/2=sinB/3
3sin25=2sinB
sinB=.634
B=sin^-1(.634)
B=39.346
39.346degrees and 140.564degrees
sin25/2=sin115.654/a
a=4.266degrees
180-39.346-25=115.654
180-140.564-25=14.436
sin25/2=sin14.436/a
a=1.180degrees