Law of Sines :)))

In C lass this last week one of the lessons learned was Law of Sines.

When using the Law of Sines, it is used on in a nonright triangle when you have a “pair”(angle of opp. Side)

The Formula is Sin A/a= Sin B/b = Sin C/c

When solving,you cross multiply.

For inverses you will get two answers,which you then have to see if they work

Example 1: Solve each triangleABC.

Angle A= 45 degrees, Angle B= 60 degrees,and a = 14

The opposite pair is sin45/14.

To solve for little b, you are going to set up a proportion.

Sin45/14 = sin60/b

After cross multiplying, you end up getting bsin24/sin45 = 14sin60/sin45

Divide each side by sin45 to get little b by itself and you then get b=14sin60/sin45

This equals 17.146

Now to solve for little c, you set up sin45/14 = sin75/c

csin45/sin45 = 14sin75/sin45

c=14sin75/sin45 =19.124

Angle A= 45 degrees, Angle B= 60 degrees, C = 75 degrees, a = 14 b = 17.146, and c =19.124