9-3

angle B=60 degrees
angle A=45 degrees
a=14

sin45/14=sin 60/b                                sin45/14=sin75/c                   180-45-60=75
b=17.146                                            c=19.124                               angle C=75 degrees

For law of sines, you have to have a pair to solve the triangle.  When you have a pair, you set it equal to the other side or angle you are given and solve.  In this problem, you are given the measure of angle B and angle A.  You are also given side a which is 14.  Since we are given both the angle and side A, then you use that as your pair.  You put sin of 45 over 14 equal to the other number you are given which is angle B.  You cross multiply and solve for side b.  Next you have to find your last angle, so you subtract the angles you already have by 180 and you get 75.  Then you have to find the last side of the triangle.  You use the pair you were given in the beginning which is sin 45/14 and set it equal to the angle and side you want to find which is c.  You cross multiply again and get that c is equal to 19.124.