Sunday, October 16, 2011

Law of Sines.

One of the 3 lessons that we've learned this past week is Law of Sines.

When using the Law of Sines, it is used on in a nonright triangle when you have a “pair”(angle of opp. Side).

The Formula is Sin A/a= Sin B/b = Sin C/c

When solving,you cross multiply.

For inverses you will get two answers,which you then have to see if they work.


Example : Solve each triangleABC.

Angle A= 58 degrees, Angle B= 65 degrees,and a = 11

The opposite pair is sin58/11.

In order to solve for little b, you must set up a proportion.

Sin58/11 = sin65/b

Cross multiply then you'll end up getting bsin58 = 11sin65

Divide each side by sin58 to get little b by itself and you then get b=11sin65/sin58

b equals 11.7556

To solve for little c, you set up sin58/11 = sin57/c

csin58=11sin57

Dive by sin 58

c=10.8784


Angle A= 58 degrees, Angle B= 65 degrees, C = 57 degrees, a = 11 b = 11.7556, and c =10.8784

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