One of the 3 lessons that we've learned this past week is Law of Sines.
When using the Law of Sines, it is used on in a nonright triangle when you have a “pair”(angle of opp. Side).
The Formula is Sin A/a= Sin B/b = Sin C/c
When solving,you cross multiply.
For inverses you will get two answers,which you then have to see if they work.
Example : Solve each triangleABC.
Angle A= 58 degrees, Angle B= 65 degrees,and a = 11
The opposite pair is sin58/11.
In order to solve for little b, you must set up a proportion.
Sin58/11 = sin65/b
Cross multiply then you'll end up getting bsin58 = 11sin65
Divide each side by sin58 to get little b by itself and you then get b=11sin65/sin58
b equals 11.7556
To solve for little c, you set up sin58/11 = sin57/c
csin58=11sin57
Dive by sin 58
c=10.8784
Angle A= 58 degrees, Angle B= 65 degrees, C = 57 degrees, a = 11 b = 11.7556, and c =10.8784
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