9-3 Law of Sines

-This week we learned law of sines. When learning law of sines you can only use in a non-right triangle when you have a "pair" (An anlge and opposite side).

-You crose multiply to slove and you will have two answers for inverse (must check to see if it works).

-Formula: sinA/a = sinB/b = sinC/c

Example 1:

The first thing we're gonna do is find little c. So you put sin45 over 14 equals sin75 over little c. Then you cross multiply and you get csin45 equals 14sin75. You need to solve for c so you divide by sin45 and you get c equals 14sin75/sin45. Plug that into you claculator and you get around 19.124

Now we're gonna solve for little b. You gonna put sin45 over 14 equals sin60 over little b. Then you will cross multiply again and you will get bsin45 equals 14sin60. You need to solve for little b so you will divide by sin45 and you will get b equals 14sin60/sin45. Plug into your calculator and you get around 17.146

Now to finish off the triangle you will need to find angleC so you subtract 180-60-45 and that gives you 75 degrees.

Fill in the rest of the triangle so Brob won't take off points and then your done.

---Danielle :)